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(2x+2)^2-64=0
We move all terms containing x to the left, all other terms to the right
(2x+2)^2=64
| 8c-9c+16=11 | | 5x+5=40x-4x | | 2(5x+3)-+6(x-4)=48 | | 8g-10g=24 | | (2x+2)^2=64 | | 7c+1=2c-7 | | 5.4g+3=3.4g+11 | | 7(3x-6)=12(2+2x) | | 63+(x+21)=3x | | 65=n-39 | | 7(3x-6)=1292+2x) | | 7(3x-6)=1292+2x | | 41-x=82 | | 4x+6=10x-14 | | 40=n-30 | | C-7=5c+5 | | 5x-4÷2x=2 | | 4x+6=10x+14 | | x2−15x+54=0 | | 80=n-128 | | 7(a-4)+10=12-3a | | x2+5=11 | | b-5b=20 | | 20=n-14 | | 10⋅x√=32−2 | | -42=0.6k | | 2x2−8x+6=0 | | -24=-0.6k | | 75=n-36 | | 6y–20=2y–4 | | x+16+3x+8=64 | | 3x+8+x+16=64 |